In ClF_3 molecule,if the lone pair of the cen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $ClF_3$ molecule has $sp^3d$ hybridization with $2$ lone pairs and $3$ bond pairs. According to $VSEPR$ theory,lone pairs occupy equatorial po

Vedclass · Accepted Answer

All are correct

Vedclass · Answer

(D) The $ClF_3$ molecule has $sp^3d$ hybridization with $2$ lone pairs and $3$ bond pairs. According to $VSEPR$ theory,lone pairs occupy equatorial positions to minimize repulsion. If the lone pairs were to occupy axial positions,the molecule would adopt a $T$-shaped geometry with a $120^o$ bond angle between the equatorial fluorine atoms. In this hypothetical configuration,the molecule would be non-polar due to the symmetric arrangement of the polar $Cl-F$ bonds,and the shape would be trigonal planar. Since all these statements describe the consequences of the lone pairs occupying axial positions,the correct option is $D$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $XeF_4$	$I$. Square pyramidal
$B$. $ClF_3$	$II$. Pentagonal bipyramidal
$C$. $BrF_5$	$III$. Square planar
$D$. $IF_7$	$IV$. Bent $T$-shape

In $ClF_3$ molecule,if the lone pair of the central atom occupied the axial position,then which of the following statements is correct?

Similar Questions

Among the following,the pair in which the two species are not isostructural is

Which of the following is isostructural with $CO_2$?

In which of the following options,molecules are correctly arranged with respect to their bond angles?

Match the following:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $XeF_4$ $I$. Square pyramidal

$B$. $ClF_3$ $II$. Pentagonal bipyramidal

$C$. $BrF_5$ $III$. Square planar

$D$. $IF_7$ $IV$. Bent $T$-shape

Although geometries of $NH_3$ and $H_2O$ molecules are distorted tetrahedral,bond angle in water is less than that of ammonia. Discuss.

Vedclass Test Series

Exam Paper Generator

Online Exam Module